0

Guest

Courses New

The initial prssure of COCl2 is 1000 torr.The total pressure of the system becomes 1500 torr.when the equilb COCl2(g)=CO(g) + Cl2(g).(reversible) is attained at constant temp.The value of Kp ?

The initial prssure of COCl2 is 1000 torr.The total pressure of the system becomes 1500 torr.when the equilb COCl2(g)=CO(g) + Cl2(g).(reversible) is attained at constant temp.The value of Kp ?

Grade:12

2 Answers

Naveen Kumar
askIITians Faculty 60 Points
9 years ago
The given reaction is :
CoCl2(g).......................................=.......CO(g).....+.....Cl2(g)
1000 torr..................................................0...............0.....................(initially)
1000-p.....................................................p...............p....
let p is the pressure of CO as well as of CL2.n so same partial pressure of COCl2 will be decreased
So total pressure at equilibrium=1000-p+p+p=1000+p=1500
Now calculate p .
Writing, Kp=pCO*pCl2/pCOCl2
=p*p/(1000-p)
now we can get Kp

Ramreddy IIT Patna
askIITians Faculty 49 Points
9 years ago
COCl2 -------> CO + Cl2
1000 torr (initial)
1000(1-x) 1000x 1000x
Total pressure= 1000(1+x)
= 1500
x= 0.5 or (50% dissociation)
Kp= (pCl2)(pCO)/(pCOCl2)
= 500 X 500 /500
you will get the answer.
….….….….….….….….….….….….….….….….….….….….…....

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More