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Amit Saxena Grade: upto college level
        The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)

a. -3.4 e V
b. -4.2 e V
c. -6.8 e V
d. +6.8e V
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
										Sol. Energy of electron in H-atom is determined by the expression

E_n = 13.6/n^2 eV where, n = 1, 2, 3,….
In excited states, E_2 = - ( 13.6)/4 = - 3.4 eV
E_3 = ( 13.6)/9 = - 1.51 eV etc.
3 years ago
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