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Here, we are given the percent ionic character = 17% =0.17, so if r is the bond distance,
The dipole moment of HCL is (0.17e)r = (0.17 x 1.6 x 10–19 C) r
= (1.03 x 3.33 x 10–30 C m)
r = 1.03 x 3.3356 x 10–30 Cm / 0.17 x 1.6 x 10–19 C
Thus, we have bond distance= 1.27 x 10–10 m = 127 pm
Thanks & Regards,
Vasantha Sivaraj,
askIITians faculty
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