0

Guest

Courses New

Sir, help me to solve with easiest description you can.

Sir, help me to solve with easiest description you can.

Question Image
Grade:11

1 Answers

Himanshu
103 Points
7 years ago
 
No of moles of CO2 initially = weight of substance(gm)/ molecular mass
No.of moles of CO2 initially = 0.2/44 = 1/220 mol
No. of moles removed = no. of molecules/ avagardo constant
No. of moles removed = 1021/ (6 × 1023) = 1/600 mol
No. of moles left = 1/220 – 1/600 = 0.028 (approx.)
 
I have already given you the above answer.This is the most simplest possible answer however if you do not get anything please ask.

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More