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Q1. Which among the following factor is the most important in making F the strongest oxidising agent? a hydration enthalpy b elctron gain enthalpy c ionisation enthalpy d bond dissociation enthalpy ans is option d but why sir?? Q2. If the aufbau principle is not being followed , Ca(Z=20) wud have been placed in a s block b p block c d block d f block Q3. Lower oxidation state is stable when difference in ionisation potential is about a 14eV b 16eV c 10eV d 18eV PLEASE GIVE ME RESONS FOR THE ANSWERS.

Q1. Which among the following factor is the most important in making F the strongest oxidising agent?
a hydration enthalpy
b elctron gain enthalpy
c ionisation enthalpy
d bond dissociation enthalpy
ans is option d but why sir??
 
Q2. If the aufbau principle is not being followed , Ca(Z=20) wud have been placed in
a s block
b p block
c d block
d f block
 
Q3. Lower oxidation state is stable when difference in ionisation potential is about
a 14eV
b 16eV
c 10eV
d 18eV
 
PLEASE GIVE ME RESONS FOR THE ANSWERS.

Grade:11

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
Q1
ans-because the weak bond enthalpy it easily form F- ion which makes it the strongest oxidising agent .Due to repulsion between the lone pair of electron on the two atoms.It makes the molecule less reactive and hence it forms F- ion easily
Q2(c)
Z=40
Electronic configuration withou afbau principle
1s^2 2s^2 2p^6 3s^2 3p^6 3d^2
so the last electron enters in d orbital it should be dblock element

Q3(b)
If the difference between IP<15ev then higher oxidation state will be stable but if the difference >16ev (Na+>Na+2)then lower oxidation state will be stable

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