Please help in sloving this question - Determine the de Broglie’s wavelength of electron emitted by a metal whose treshold frequency is 2.25 * 10 14 Hz when exposed to visible radiation of wavelenghth 500nm.

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abhishek kumar · Answer

please use the equation lamda=h/

abhishek kumar · Answer

please use the equation lamda =h/( 2mKE) where KE is kinetic energy of electron. we get KE by sbtracting threshold energy from energy of radiation ie; energy of radiation -threshold energy kndly please do the calculation by yourself .

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Please help in sloving this question - Determine the de Broglie’s wavelength of electron emitted by a metal whose treshold frequency is 2.25 * 10 14 Hz when exposed to visible radiation of wavelenghth 500nm.

Please help in sloving this question -
Determine the de Broglie’s wavelength of electron emitted by a metal whose treshold frequency is 2.25 * 10¹⁴Hz when exposed to visible radiation of wavelenghth 500nm.

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Please help in sloving this question - Determine the de Broglie’s wavelength of electron emitted by a metal whose treshold frequency is 2.25 * 10 14 Hz when exposed to visible radiation of wavelenghth 500nm.

Please help in sloving this question -Determine the de Broglie’s wavelength of electron emitted by a metal whose treshold frequency is 2.25 * 1014Hz when exposed to visible radiation of wavelenghth 500nm.

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Please help in sloving this question -
Determine the de Broglie’s wavelength of electron emitted by a metal whose treshold frequency is 2.25 * 10¹⁴Hz when exposed to visible radiation of wavelenghth 500nm.