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Please explain how it is calculated.. Question is attached.. [ALTS-2 Q72]

Please explain how it is calculated..
Question is attached..
 
[ALTS-2 Q72]

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Grade:12th pass

1 Answers

Naveen Kumar
askIITians Faculty 60 Points
9 years ago
The elements will be =2+8+8+18+18+32+32+50+50+(50+22)
corresponding to 1st,2nd,3rd,..............10th period.
In 9thperiod, number of orbitals=1(s)+p(3)+d(5)+7(f)+9(g)=
total elements in 10thperiod=2*(available orbitals in this period) =
2*[1(s)+p(3)+d(5)+7(f)+9(g)+ 11(h)]=
The configuration can be given as:
260-1801_Capture.PNG

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