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Orbital angular momentum of an electron is √3h÷π then the numbers of orientation of this orbital in space is

Orbital angular momentum of an electron is √3h÷π then the numbers of orientation of this orbital in space is

Grade:11

1 Answers

saarang
23 Points
6 years ago
Root of l(l+1) * h/2pie = orbital angular momentum= root 3 * h/pie......On simplifying we get that l is equal to 2 or -3.... -ve can`t be the answer hence l=2 ie d orbital

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