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how many moles of al2(so4)3 would be present in 50g of the substances (given at volume at al=27,s=32,o=16)

how many moles of al2(so4)3 would be present in 50g of the substances  (given at volume at al=27,s=32,o=16)

Grade:12

1 Answers

MD Badruddowja
19 Points
6 years ago
1 mole Al2(SO4)3= 342.15 g.
so, 342.15 g Al2(SO4)3 = 1 mole
50 g of Al2(SO4)3 contains 1*50/342.15 mole= .146 mole
 

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