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how many iron atms are present in a stainless steel ball bearing having a radius of 0.1 inch (1 inch=2.54cm) ? the stainless steel contains 85.6% Fe by weight and has a density of 7.75 g/cc?

how many iron atms are present in a stainless steel ball bearing having a radius of 0.1 inch (1 inch=2.54cm) ? the stainless steel contains 85.6% Fe by weight and has a density of 7.75 g/cc?

Grade:11

1 Answers

DILIP
116 Points
7 years ago
Given that the radius of the ball is 0.254 cm.
Volume of the ball is 4/3 π r3 .
Volume is   0.0686 cc.
mass of steel ball is = Density of ball x Volume of ball .
Mass = 7.75 x 0.0686 = 0.53165 g .
  mass percent of Fe in ball is 85.6%
 Mass of Fe in ball  =  ( 0.53165 x 85.6 ) / 100   =  0.455 g .
55.8 g of Fe    =    1 mol of Fe .
0.455 g of Fe  =    0.00815 moles of Fe.
 
1 mol of Fe contains …..  6.023 x 1023 atoms.
0.00815 moles of Fe contains ….… ????
 
= ( 6.023 x 1023  ) x ( 0.00815 )
= 4.908 x 1021  iron atoms are present in the given stainless steel ball.

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