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For the given EQ. L(gas) ---------> M(gas), K(forward) = 5 * 10^-4 mol/L/Sec K(back) = 3 * 10^-2 L/Mol/sec, then equilibrium concentration of M is

For the given EQ.
L(gas) ---------> M(gas), 
K(forward) = 5 * 10^-4 mol/L/Sec
K(back) = 3 * 10^-2 L/Mol/sec, then
equilibrium concentration of M is

Grade:12th pass

2 Answers

Karan Yadav
33 Points
9 years ago
Keq=Kf/Kb
1.66 x 10^-2
Arpit Dhankar
33 Points
9 years ago
But answer is not K.eq
 

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