Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at o6C - will be : [ fK for water = 1.86 K kg mol 1 - , and molar mass of ethylene glycol = 62g mol 1 - )

Question

Sunil Kumar FP · Answer

freeaing temperature is not clear-I think it is .06degree celsius
let the mass of the ethlyene glycol be m
molality of the mixture is = $\frac{m}{62*4}$
we have deltaTf=Kfm,where m is the molaity of the solution
.06=1.86m/248
m=8 gram

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Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at o6C - will be : [ fK for water = 1.86 K kg mol 1 - , and molar mass of ethylene glycol = 62g mol 1 - )

Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at o6C - will be : [ fK for water = 1.86 K kg mol 1 - , and molar mass of ethylene glycol = 62g mol 1 - )

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Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at o6C - will be : [ fK for water = 1.86 K kg mol 1 - , and molar mass of ethylene glycol = 62g mol 1 - )

Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at o6C - will be : [ fK for water = 1.86 K kg mol 1 - , and molar mass of ethylene glycol = 62g mol 1 - )

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