Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Shane Macguire Grade: upto college level
```        Equal weights of methane and oxygen are mixed in an empty container at 25°C. The fraction of the total pressure exerted by oxygen is
a. 1/3
b. 1/2
c. 2/3
d. 1/3  ×  273/298
```
3 years ago

396 Points
```										Sol.  If x g of both oxygen and methane are mixed then :
Mole of oxygen = x/32
Mole of methane = x/16
⇒ mole fraction of oxygen = (x/32)/(x/32  + x/16)  =  1/3
According to law of partial pressure
Partial pressure of oxygen (po2) = mole-fraction × total pressure
⇒  〖Po〗_2/p  =  1/3

```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 2,385 off
USE CODE: COUPON10
Get extra Rs. 413 off
USE CODE: COUPON10