Diboorane b2h6 can be prepared by the reaction
3NaBH4 + 4BF3 GIVES 3NaBF4 + 2B2H6
If the reaction has 70 % yield ,how many moles of NaBH4 should be used with excess BF3 in order to obtain 0.200 moles of B2H6

Question

Sunil Kumar FP · Answer

3NaBH4 + 4BF3--------3NaBF4 + 2B2H6 1 mole of b2h6 produces 1.5 mole of nabh4 .2 mole of b2h6 will produce (1.5*10*10)/14=10.7 mole sice the yield is 70%

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Diboorane b2h6 can be prepared by the reaction 3NaBH4 + 4BF3 GIVES 3NaBF4 + 2B2H6 If the reaction has 70 % yield ,how many moles of NaBH4 should be used with excess BF3 in order to obtain 0.200 moles of B2H6

Diboorane b2h6 can be prepared by the reaction
3NaBH4 + 4BF3 GIVES 3NaBF4 + 2B2H6
If the reaction has 70 % yield ,how many moles of NaBH4 should be used with excess BF3 in order to obtain 0.200 moles of B2H6

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Diboorane b2h6 can be prepared by the reaction 3NaBH4 + 4BF3 GIVES 3NaBF4 + 2B2H6 If the reaction has 70 % yield ,how many moles of NaBH4 should be used with excess BF3 in order to obtain 0.200 moles of B2H6

Diboorane b2h6 can be prepared by the reaction3NaBH4 + 4BF3 GIVES 3NaBF4 + 2B2H6If the reaction has 70 % yield ,how many moles of NaBH4 should be used with excess BF3 in order to obtain 0.200 moles of B2H6

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Diboorane b2h6 can be prepared by the reaction
3NaBH4 + 4BF3 GIVES 3NaBF4 + 2B2H6
If the reaction has 70 % yield ,how many moles of NaBH4 should be used with excess BF3 in order to obtain 0.200 moles of B2H6