calculate the amount of NH4Cl required to be dissolved in 500ml water to have ph=4.5 [ Kb for NH4OH=1.8 * 10^-5]

Question

calculate the amount of NH4Cl required to be dissolved in 500ml water to have ph=4.5 [ Kb for NH4OH=1.8 * 10^-5] ​

Sakshi · Answer

this is just the question of buffer and that too a basic buffer first find out the number of moles of both the ammonium ion and the salt concentration and u ll get the answer

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calculate the amount of NH4Cl required to be dissolved in 500ml water to have ph=4.5 [ Kb for NH4OH=1.8 * 10^-5]

calculate the amount of NH4Cl required to be dissolved in 500ml water to have ph=4.5 [ Kb for NH4OH=1.8 * 10^-5]

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calculate the amount of NH4Cl required to be dissolved in 500ml water to have ph=4.5 [ Kb for NH4OH=1.8 * 10^-5] ​

calculate the amount of NH4Cl required to be dissolved in 500ml water to have ph=4.5 [ Kb for NH4OH=1.8 * 10^-5]​

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calculate the amount of NH4Cl required to be dissolved in 500ml water to have ph=4.5 [ Kb for NH4OH=1.8 * 10^-5]

calculate the amount of NH4Cl required to be dissolved in 500ml water to have ph=4.5 [ Kb for NH4OH=1.8 * 10^-5]