0

Guest

Courses New

calcu;late EMF of the cell A/A3+(0.1m)// B2+(0.01m)/B given Eo A/A3+=0.75V Eo B/B2+= 0.45V

calcu;late EMF of the cell 
A/A3+(0.1m)// B2+(0.01m)/B
given Eo A/A3+=0.75V
Eo B/B2+= 0.45V

Grade:12

1 Answers

Naveen Kumar
askIITians Faculty 60 Points
9 years ago
The half cell reactions can be written as: A............>...A3+(0.1M)..+3e-................(1)
at anode
and for cathode, B2+(0.01M)........+2e-................>B.............(2)
For balencng the e4quations multiply (1) with 2 and (2) with 3 and add both.
Now calculate free energy change for individual haifs and then add the free energy change.
First calculate E by using formula E=Eo-0.0591/n *logQ
where Q=reaction quotient=[A3+] for equation (1) and 1/[B2+] for equation(2).and now calculate deltaG value for the half reactions.
deltaG=-nFE, where n-=number of electrons involved
and after adding the delta G again use the same formula to get the value of E for the overall reaction.


Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More