At NTP what is the vOldmeldrum of 6.022×10^23 in H2 GAS

Question

Arun · Answer

6.023 * 10^23 = 1 mol 1 mole of any gas occupies 22.4 litres at STP. So the volume of molecule of 6.023* 10^23 of H2 = 22.4 litres

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At NTP what is the vOldmeldrum of 6.022×10^23 in H2 GAS

At NTP what is the vOldmeldrum of 6.022×10^23 in H2 GAS

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At NTP what is the vOldmeldrum of 6.022×10^23 in H2 GAS

At NTP what is the vOldmeldrum of 6.022×10^23 in H2 GAS

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