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At 250 degree C the vapour density of PCl5 is 100 calculate the degree of disociation at this temperature ?

Grade:12th pass

1 Answers

Vikas TU
14149 Points
7 years ago
 
The Reaction for the PCl5 is:
PCl5 ====>     PCl3    + Cl2
n = 1 + 1 = 2
Now the degree of dissociation related o the theoretical mass and the observed mass is:
a = (Mth – Mobs.)/Mth.(n -1)
a = (208.24 – 200)/(208.4*(2-1)) => 0.039 or 3.9% disscocitaion.

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