0

Guest

Courses New

Arrange the following in increasing oxidation number of iodine. I 2 , HI , HIO 4 ,ICI

Arrange the following in increasing oxidation number of iodine.
I2, HI, HIO4,ICI

Grade:upto college level

2 Answers

Navjyot Kalra
askIITians Faculty 654 Points
9 years ago
HI < I2< ICI < HIO4; O.N. of I in I­2 = 0, HI = - 1, ICI = + 1, HIO4 = + 7.
Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
I2 oxidation number=0
HI=-1
HIO4=+7
ICL=+1
increasing oxidation number=I2,HI,ICL,HIO4
thanks and regards
sunil kr
askIITian faculty

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More