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Amit Saxena Grade: upto college level
        An aqueous solution containing 0.01 g KIO3 (formula weight = 214.0) was treated with an excess of KI solution. The solution was acidified with HCI. The liberated I2 consumed 45.0 mL of thiosulphate solution decolourise the blue starch-iodine complex. Calculate the molarity of the sodium thiosulphate solution.
3 years ago

Answers : (1)

Jitender Pal
askIITians Faculty
365 Points
										Sol. The redox reaction involved are :

〖IO〗_3^- + 5I- + 6H+ → 3I2 + 3H2O
I2 + 2S2O_3^(2-) → 2I- + S4O_6^(2-)
Millimol of KIO3 used = 0.1/214 × 1000 = 0.467
⇒ millimol of I2 formed
= 3 × 0.467 = 1.4
⇒ millimol of Na2S2O3 consumed = 2 × 1.4 = 2.8
⇒ Molarity of Na2S2O3 = 2.8/45 = 0.062 M
3 years ago
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