Ammonia contains 82.65 % N and 17.65% H2. If the law of constant proportions is true, then the mass of nitrogen required to give 10 g Ammonia will be:

Question

Vikas TU · Answer

The chemical eqn. would be: N2 + H2 ------------> 2NH3 10/17 moles moles of N2 = 5/17 mass of N2 = 5*28/17 = 8.235 gm Nitrogen

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Ammonia contains 82.65 % N and 17.65% H2. If the law of constant proportions is true, then the mass of nitrogen required to give 10 g Ammonia will be:

Ammonia contains 82.65 % N and 17.65% H2. If the law of constant proportions is true, then the mass of nitrogen required to give 10 g Ammonia will be:

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Ammonia contains 82.65 % N and 17.65% H2. If the law of constant proportions is true, then the mass of nitrogen required to give 10 g Ammonia will be:

Ammonia contains 82.65 % N and 17.65% H2. If the law of constant proportions is true, then the mass of nitrogen required to give 10 g Ammonia will be:

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