0

Guest

Courses New

AB; crystallizes in a body centred cubic lattice with edge length ‘a equal to 387pm. The distance between two oppositely charged ions in the lattice is : (a) 335 pm (b) 250 pm (c) 200 pm (d) 300 pm

AB; crystallizes in a body centred cubic lattice with edge length ‘a equal to 387pm. The distance between two oppositely charged ions
in the lattice is :
(a) 335 pm
(b) 250 pm
(c) 200 pm
(d) 300 pm

Grade:9

2 Answers

Vikas TU
14149 Points
6 years ago
The distance b/w them would be ;
2r = root(3)*a/2
2r => 387*root3/2 => 335 pm approx.
This would be the distance b/w the two opposite charges.
Athira
13 Points
5 years ago
The distance between opposite charges would be :
r=√3*a/4 here the edge length ,a is given by 387pm 
Implies r = √3 *387 /4 
We get 335 approximately .. 

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More