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A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of CO2. The empirical formula of the hydrocarbon is

A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of CO2. The empirical formula of the hydrocarbon is

Grade:12

2 Answers

nvenktesh reddy
20 Points
7 years ago
CxHy + zO2 =xCO2 +y/2H2O.We can find the empirical formula of the hydrocarbon from the next ratio:(x/y)=(m(CO2)/M(CO2)):(m(H2O)/(M(H2O))=(3.08gm/44gm/mol):(0.72gm/(18gm/mol/2))=0.07:0.08=7:8.Thus,the empirical formula of the hydrocarbon is C7H8
Rishi Sharma
askIITians Faculty 646 Points
3 years ago
Dear Student,
Please find below the solution to your problem.
645-631_00002020.PNG
Moles of H2​O = 0.72/18 ​= 0.04
Moles of CO2 ​= 3.08/44​ = 0.07
y/2 ​= 0.04×100 or y=8 , x = 0.07 ×100 = 7
Empirical formula is C7​H8

Thanks and Regards

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