a drop of water weighs 0.025 grams. Of this drop evaporates in one minute, the number of molecules escaping per second from the surface are?

Question

Harishwar · Answer

18 grams of water = 1 mole of water = 6.023*10^23 molecules of water
0.025 grams of water = 0.001388 mole of water = 0.00836*10^23 molecules of water
So 0.00836*10^23 molecules of water evaporates per min
i.e 0.00836*10^23 /60 molecules of water evaporates per sec

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a drop of water weighs 0.025 grams. Of this drop evaporates in one minute, the number of molecules escaping per second from the surface are?

a drop of water weighs 0.025 grams. Of this drop evaporates in one minute, the number of molecules escaping per second from the surface are?

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a drop of water weighs 0.025 grams. Of this drop evaporates in one minute, the number of molecules escaping per second from the surface are?

a drop of water weighs 0.025 grams. Of this drop evaporates in one minute, the number of molecules escaping per second from the surface are?

1 Answers

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