5 moles of an ideal gas expand isohermally and reversibly from pressure of 10atm to 2atm at 300K. what is largest mass [approx] which can be lifted through hieght 1 m in this expansion?

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Vikas TU · Answer

Work done isothermally in reversible process is given as: W = – nRT * log(P1/P2) put all the values, W = – 5R*300*log(10/2) = > 20 KJ (approx.) W = F x displacement = > mgd where d = 1 m. W = 20,000 = 10m m = 2000/1000 = 2 kg.

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5 moles of an ideal gas expand isohermally and reversibly from pressure of 10atm to 2atm at 300K. what is largest mass [approx] which can be lifted through hieght 1 m in this expansion?

5 moles of an ideal gas expand isohermally and reversibly from pressure of 10atm to 2atm at 300K. what is largest mass [approx] which can be lifted through hieght 1 m in this expansion?

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5 moles of an ideal gas expand isohermally and reversibly from pressure of 10atm to 2atm at 300K. what is largest mass [approx] which can be lifted through hieght 1 m in this expansion?

5 moles of an ideal gas expand isohermally and reversibly from pressure of 10atm to 2atm at 300K. what is largest mass [approx] which can be lifted through hieght 1 m in this expansion?

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