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5.3 gms of NA2CO3 ARE DISSOLVED IN 100 ML OF WATER,THEN NORMALITY OF THE SOLUTION IS

5.3 gms of NA2CO3  ARE DISSOLVED  IN 100 ML OF WATER,THEN NORMALITY OF THE SOLUTION IS


 

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3 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
10 years ago
normality=wt/eqwt×v(l)
here eq wt=mw/2=106/2=53
therefore ,normality=5.3/53×.1=1N

thanks and regard
sunil kumar
ask iitian
KARTHIK
38 Points
10 years ago
Normality=wt/eqwt×1000/v(ml) (5.3÷106)(1000÷100=0.5
KARTHIK
38 Points
10 years ago
Normality=wt/eqwt×1000/v(ml) (5.3÷106)(1000÷100)=0.5

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