250m of 0.5M KCL is diluted with water in 500ml solution. What will be the number of chloride ions in the resulting solution

Question

Vikas TU · Answer

Dear Student,
Here in 1 lit it is 0.5 M.
In 250/ml It is 0.5/4=0.125 M
So, in case of resting solution the no of chloride ions are 0.125N/750 [N is avigadro np].

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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250m of 0.5M KCL is diluted with water in 500ml solution. What will be the number of chloride ions in the resulting solution

250m of 0.5M KCL is diluted with water in 500ml solution. What will be the number of chloride ions in the resulting solution

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250m of 0.5M KCL is diluted with water in 500ml solution. What will be the number of chloride ions in the resulting solution

250m of 0.5M KCL is diluted with water in 500ml solution. What will be the number of chloride ions in the resulting solution

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