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saumya verma Grade:
        a solution is prepared by dissolving 516.5mg of oxalic acid to make 100ml of solution.A 10ml portion is then diluted to 250ml.what is the molarity of the final solution.
7 years ago

Answers : (1)

Gaurav
askIITians Faculty
164 Points
										.5165 g x (1mole)/(90g) = number of moles= .0057388

Molarity=.0057388moles/.1liters=.05738... solution

(.057388 moles/liter) X (10ml/250ml)=.002295
On calculating we get correct solution as0.02M
2 years ago
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