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determine the dgree of disociation of 0.05 m NH3 at 250 in a solution of ph=11    

6 years ago


Answers : (1)

										nh3 + h2o----nh4+  oh-
let the degree of dissociation be x
nh4+= .05x
oh- =10^-3 +.05x
value of k not given
find x from this eqn=
k=.05x(10^-3 +.05x)/.05(1-x)

2 years ago

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