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```        degree of dissociation of weak monoprotic  acid can be given as
(A) a= 1/[1+10(pKa+pH)]
(B) a=1/[1+10(pKa-pH)]
(C) a=1/[1+10(-pKa+pH)]
(D) a=1/[1+10(pKa/pH)]
7 years ago

47 Points
```										Dear Student MS. shefali,

HA    ==   H+   +   A-
c(1-a)     ca       ca

Ka = ca2/(1-a)

c= (1-a)/a2 * Ka...............(1)

H+ = ca

c = H+/a....................(2)

by equation 1 and 2
H+/a == (1-a)/a2 * Ka

H+ == (1-a)/a * Ka

H+/Ka == (1-a)/a

H+/Ka == (1/a)-1

(H+/Ka) +1 == (1/a)

[10(-pH)]/[10(-pKa)] + 1 == (1/a)

[10(pKa-pH) + 1] == (1/a)

a=1/[1+10(pKa-pH)]

So B option is correct.
Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed
solution very  quickly.

All the best.
Regards,
Pramod Kumar
IITR Alumni

```
7 years ago
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