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2.2g of a compopund of phosphorous and sulphur has1.24g of P in it Determine its empirical formula
Dear pallavi
percentage of sulpher = 1.24/2.2 *100 =56.4
percentage of P = 100-56.4 =43.6
relative number of molecules of S = 56.4/32 = 1.76
relative number of molecules of P = 43.6 /31 = 1.41
intigral ratio of sulpher is =5
intigral ration of P = 4
so imperical formula = P4S5
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