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Determine the molecular formula of an oxide of sulphur containing 50% sulphur
Dear pallavi
percentage of sulpher =50%
percentage of oxygen = 100-50 =50%
number of molecule of sulpher = 50/32=1.5625
number of molecules of oxygen = 50/16 =3.125
so simple ration of molecules are = S/O = 1/2
so emperical formula = SO2
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