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Chandan Das Grade: Upto college level
```        1.What is equilibrium molarity?Plz xplain a bit?
2.What is equivalent mass?How can we get the eqv mass of any species 4m a rxn?```
8 years ago

Ramesh V
70 Points
```										(1) I'll explain through examples :
Calculate the equilibrium molarities of H2, I2, and HI
H2(g) + I2(g) <--> 2 HI(g) Initial..................... 0.05.... 0.06 ...........0 Change...................- x ......- x..............+x Equilibrium.......... 0.05 - x.. 0.06-x...........x Equilibrium constant, Kc = [HI]2 / [H2] [I2] = 58.6 ......................................… = [x]2 / [0.05-x] [0.06-x] = 58.6 Solve for x to get the change in the number of moles, and subsequently the number of moles of each compound in equilibrium Molarity of H2 = [0.05-x] / 1.00L Molarity of I2 = [0.06-x] / 1.00L Molarity of HI = x / 1.00L
(2)
Equivalent weight is the atomic weight of an element or radical divided by the valence it assumes in a chemical compound.
5H2SO4+8NaI=4Na2SO4+H2S+4H2O+4I2
By definition one equivalent (or equivalent weight) of a substance is the amount of that substance which supplies or consumes one mole of reactive species. In acid-base chemistry the reactive species is the hydrogen ion (H+) while in oxidation-reduction chemistry the reactive species is the electron. Since this is an acid-base reaction, we need to follow the rules in getting equivalent weights appropriate for this kind of reaction. From the equation, we can conclude that there are 4 reactive hydrogen ions based from the produced H2O. EW = Molar Weight (MW) / (No. of Equivalence / No. of Moles) EW = (98.0791 g/mol) / (4 eq / 5 mol) = 122.6 g/eq Hope that helps! :)
--
regards
Ramesh

```
7 years ago
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