Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
find pressure at which the PV vs P curve acquires minima for 1 mole of oxygen gas at 0°C . a=1.36 L² atm mol‾² , b=32 cm³ mol¯¹
for n=1, T=273K
the eqn is : PV = Pb + RT + ab/V2 - a/V --- (1)
differentiating for minima , d(PV)/dV = 0 whihc gives
0 = -2ab/V3 + a/V2
so V = 2b .. (2)
hence on substituting V,a,b,R,T, and putting (2) in (1)
we get P = RT/b - a/4b2
on substituting values you can easily get value of P
--
regards
Ramesh
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !