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abhishek kumar sharma Grade: 11
        

find pressure at which the PV vs P curve acquires minima for 1 mole of oxygen gas at 0°C .    a=1.36 L² atm mol‾² , b=32 cm³ mol¯¹

7 years ago

Answers : (1)

Ramesh V
70 Points
										


for n=1, T=273K


the eqn is : PV = Pb + RT + ab/V2 - a/V  --- (1)


differentiating for minima , d(PV)/dV = 0 whihc gives


0 = -2ab/V3 + a/V2


so V = 2b  .. (2)


hence on substituting V,a,b,R,T, and putting (2) in (1)


we get P = RT/b - a/4b2


on substituting values you can easily get value of P


--


regards


Ramesh

7 years ago
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