MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Samridhi Banga Grade: 11
        the rate of change of pressure (p) of a gas at constant temp and constant external pressure due to effusion of gas from a vessel of constant volume is related to rate of change of no. of molecules present by:

dp/dt=kT*dN/V*dt
where k is boltzmann constant.T=temp,V=vol. of vessel and N=no. of moles and dn/dt= -pA/ sq. root of (2pmT) , where A = area of orifice and m= mass of molecule

time reqd for pressure inside vessel to reduce to 1/e of its initial value is (ln e=1):
7 years ago

Answers : (1)

SAGAR SINGH - IIT DELHI
879 Points
										

Dear student,


Use graham's law of diffusion,
















The comparative rates of diffusion of two gases are inversely proportional to the square root of their      densities.





6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details