The catalysts decrease the Ea from 100 K J mol^-1 to 80 K J mol^-1 . At what temperature the rate of reaction in the absence of catalyst at 500 K will be equal to rate of reaction in presence of catalyst .

Question

Mujahid Ahmed · Answer

Apply Arhenius equation. K = Ae^-Ea/RT If the two Rates are equal. e^-Ea 1 /RT 1 = e^-Ea 2 /RT 2 Ea 1 /T 1 = Ea 2 /T2 100/T = 80/500 T = 625 K Approve if i helped.

ashish chauhan · Answer

the catalyst decreses the Ea from 100 kj mol to 80 kj mol .at what temperature the rate of reaction in absence of catalyst at 500 k will be equal to rate of reaction in presence of catalyst

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The catalysts decrease the Ea from 100 K J mol^-1 to 80 K J mol^-1 . At what temperature the rate of reaction in the absence of catalyst at 500 K will be equal to rate of reaction in presence of catalyst .

The catalysts decrease the Ea from 100 K J mol^-1 to 80 K J mol^-1 . At what temperature the rate of reaction in the absence of catalyst at 500 K will be equal to rate of reaction in presence of catalyst .

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The catalysts decrease the Ea from 100 K J mol^-1 to 80 K J mol^-1 . At what temperature the rate of reaction in the absence of catalyst at 500 K will be equal to rate of reaction in presence of catalyst .

The catalysts decrease the Ea from 100 K J mol^-1 to 80 K J mol^-1 . At what temperature the rate of reaction in the absence of catalyst at 500 K will be equal to rate of reaction in presence of catalyst .

2 Answers

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