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calculate the pH of 0.32 M Naoh

calculate the pH of 0.32 M Naoh

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Gaurav
askIITians Faculty 164 Points
9 years ago
pOH = -log[0.32] = - log[3.2\times 10^-1]
= – log 3.2 +1 = -0.505 +1 = 0.5
pH = 14- pOH = 14-0.5 = = 13.5

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