Grade 11Physical ChemistryThe mean KE of a molecule at 0 C is 5.621 x 10^-14 ergs. Calculate no. of molecules in gm molecule of gas. Vishrant Vasavada 16 Years agoGrade 11
askiitian.expert- chandra sekhar16 Years agoHi, KE= 3/2 nRT= 5.621 *10^-14*6.023*10^23 n= 2/3 * 562.1*6.023/8.314*273 n=0.9944 no of molecules = 0.9944* 6.023*10^23