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Grade 11Physical Chemistry

The mean KE of a molecule at 0 C is 5.621 x 10^-14 ergs. Calculate no. of molecules in gm molecule of gas.

Profile image of Vishrant Vasavada
16 Years agoGrade 11
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1 Answer

Profile image of askiitian.expert- chandra sekhar
16 Years ago

Hi,

KE= 3/2 nRT= 5.621 *10^-14*6.023*10^23

n= 2/3 * 562.1*6.023/8.314*273

n=0.9944

no of molecules = 0.9944* 6.023*10^23