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Sankalp Samuel Das Grade: 11
        

What is the Oxidation State of Sulphur in 


H2S2O8   ??

8 years ago

Answers : (5)

bibhash jha
15 Points
										+6.

This is known as peroxy di sulphuric acid(marshals acid) where peroxylinkage is there ,so six oxygen normal with -2 charge while two with -1 chrge due to peroxy linkage so sulphur oxidation number is +6 .HO-S-O-O-S-OH both sulphur attach with two cordinate oxygen atom each.
8 years ago
Pritish Kamath
8 Points
										

0=2*1+2x+ (-2)*8


where x is the oxidation state


therefore the oxidation state is 14


correct me i i am wrong somewhere


Regards

8 years ago
Ramesh V
70 Points
										

O.S for H is +1


O.S for O is -2


let O.S for S be x , then


2+2x-16=0


x=+7  is O.S of sulphur


 


 

8 years ago
anandpal shekhawat
8 Points
										Hi,

in this the two S atoms peroxy linkage between them as shown; (-S-O-O-S-) & each S has 2 double bonded O atoms & 1 -OH group. Hence, O.N. of S =+6.
8 years ago
Apoorv Jain
33 Points
										

OXIDATION STATE OF SULPHUR IS 7

7 years ago
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