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What is the Oxidation State of Sulphur in 

H2S2O8   ??

7 years ago


Answers : (5)


This is known as peroxy di sulphuric acid(marshals acid) where peroxylinkage is there ,so six oxygen normal with -2 charge while two with -1 chrge due to peroxy linkage so sulphur oxidation number is +6 .HO-S-O-O-S-OH both sulphur attach with two cordinate oxygen atom each.
7 years ago

0=2*1+2x+ (-2)*8

where x is the oxidation state

therefore the oxidation state is 14

correct me i i am wrong somewhere


7 years ago

O.S for H is +1

O.S for O is -2

let O.S for S be x , then


x=+7  is O.S of sulphur



7 years ago

in this the two S atoms peroxy linkage between them as shown; (-S-O-O-S-) & each S has 2 double bonded O atoms & 1 -OH group. Hence, O.N. of S =+6.
7 years ago


6 years ago

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