MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
singavarapu pondu raviteja Grade: 12
        

NA2SO4XH2O  ON  HEATING  SUFFERS   A LOSS  OF WEIGHT  OF  56%  THEN  FIND  X , MOL.WT ?                                                                                                                                                  

8 years ago

Answers : (2)

sasha sasha sasha
18 Points
										

Na2SO4.XH2O -> Na2SO4 + X H2O (BECOMES ANHYDROUS)


 


1MOLE              ==      1      == X MOLES            (== MEANS REACT)


 


THUS,


100/(142+18 X) == 1  == 100 X/(142+18 X)MOLES


AND WE HAVE 56/18 MOLES OF H2O (AS 56% LOST GOES IN H20).


EQUATING THEM YOU GET X = 10 MOLES .....


AND THUS CALCULTE MOL WT. YOURSELF.

8 years ago
Ramesh V
70 Points
										

on heaing it looses all water molecules


let n water molecules be present in the compound before heating


its mol. wt. is : 18n + 142


loss in mol wt after heating : 18n


18n/(142+18n) = 54/100


on solving fo rn gives : n=10


the compound is NA2SO4.10H2O


--


regards


Ramesh

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details