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Determine the concentration of hydroxyl ions in 0.4M NH4OH solution having 1)no NH4Cl 2)5.35gm of NH4Cl
ionization constant of NH4OH is 1.8*10-5
Hi Tejas,
1) NH4Cl---->NH4+ + Cl-
0.4(1-x) 0.4x 0.4x
0.4*x2/(1-x)=1.8*10-5
x2/(1-x)=4.5*10-4
as the value of ionization constant is less 1-x≈1
x2=4.5*10-4
[OH-]=2.12*10-2
2)NH4Cl completely undergoes dissociation
5.35 g of NH4Cl is 0.1 moles
x(0.1+x)/(0.4-x)=1.8*10-5
x2+x(0.1+1.8*10-5)-7.2*10-4=0
0.1+1.8*10-5≈01
x2+0.1x-7.2*10-4=0
x=6.745*10-3
[OH-]=6.745*10-3
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