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tejas sanjay akole Grade: 12
        

Determine the concentration of hydroxyl ions in 0.4M NH4OH solution having 1)no NH4Cl 2)5.35gm of NH4Cl


ionization constant of NH4OH is 1.8*10-5

7 years ago

Answers : (1)

askiitian.expert- chandra sekhar
10 Points
										

Hi Tejas,


1) NH4Cl---->NH4+ + Cl-


    0.4(1-x)      0.4x    0.4x


    0.4*x2/(1-x)=1.8*10-5


     x2/(1-x)=4.5*10-4


     as the value of ionization constant is less 1-x≈1


      x2=4.5*10-4


      [OH-]=2.12*10-2


2)NH4Cl completely undergoes dissociation


   5.35 g of NH4Cl is 0.1 moles


    x(0.1+x)/(0.4-x)=1.8*10-5


    x2+x(0.1+1.8*10-5)-7.2*10-4=0


    0.1+1.8*10-5≈01


    x2+0.1x-7.2*10-4=0


    x=6.745*10-3


   [OH-]=6.745*10-3


 

7 years ago
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