Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        I m not able to solve this question. Can u please answer with detailed solution:The density of a mixture of O2 and N2 at STP is 1.3g/litre. Calculate the partial pressure of O2.`
8 years ago

Pratham Ashish
17 Points
```										hi,
let the total no. of moles be n in which n1 are of O2 & n2 are of N2
so,   n= n1 + n2
let the volume be V ,
so density = total mass/ V
1.3   = (n1 *32  + n2 *28 )/V  ...................1
at stp , Volume of one mole gas is 22.4 lt.
so the volume of n= n1 +n2 moles =  22.4 n
V  = 22.4 (n1 + n2 )    putting in eq 1
1.3   = (n1 *32  + n2 *28 )/ 22.4 (n1 + n2 )
29.12 n1 + 29.12 n2 =  32 n1 + 28 n2
1.12 n2 = 2.88 n1
n1/n2 = .389
so, n1/n = .2801                     ( n2/n1 + 1 = (n1 +n2) /n1)
at stp total P = 101.325 k Pa
partial pressure of O2 = n1/n* P
= .2801 *101.325
= 28.37 k Pa

```
8 years ago
Nikit Saraf
18 Points
```										Thank You!! so much for the reply..
```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Physical Chemistry

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details