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ANKUR GUPTA Grade: 12
        

Given ionisation potential of H atom is 13.6eV.Find the frequency and wavelength of Hβ line of Balmer series.

8 years ago

Answers : (1)

Ramesh V
70 Points
										

In Balmer series Hβ line transition is from n1=4 to n2=2


dE = 13.6*(n1-2 -n2-2)


    = 13.6*3/16  = 2.55 eV


hc/(lamda) = 2.55 eV


lamda = hc / (2.55*1.6*10-19 )


      wavelength    = 486.12 nm


 frequency = 6.17*1014 Hz


--


Regards


Ramesh

8 years ago
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