MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
simmi singh Grade: 12
        

a strong current of trivalent gaseous boron passed thru a germanium crystal decreases d density of crystal due to part replacement of germanium by boron and due to interstitial vacancies created by missing germanium atoms.In one such xperiment one gram of germanium is taken and the boron atoms r found to be 150ppm by wt,when density of germanium crystal decreases by 4%.calculate d % of missing vacancies due to germanium which r filled up by boron atoms???


 


pls explain each step as well.


thank u.

8 years ago

Answers : (1)

askiitian.expert- chandra sekhar
10 Points
										

Hi Simmi singh,


1 g Germanium------- 150 ppm= 1.5 * 10^-4 g Boron


4% decrease---- now weight is 0.96 g(Ge + B)----0.04 g missing


0.04 missing-------- (0.04-0.00015)g Ge missing------(0.04-0.00015)/72.61 moles Ge missing=5.488*10^-4 moles


Boron replaced= 1.5*10^-4 g = (1.5*10^-4)/10 moles


                equvalently replaced = 3/4((1.5*10^-4)/10) moles of Ge    ( Valency of B is 3 and Ge is 4)


                                              = 0.1125*10^-4 moles of Ge


% of Missing vacancies filled by B atoms = 0.1125*100/5.488 = 2.05 %

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details