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Harsh Dwivedi Grade: 11
        Two moles HI were heated in a sealed tube at 440C till the equilibrium was reached.HIwas found to be 22% decomposed.The equilibrium constant for dissociation is?
7 years ago

Answers : (1)

pratham ashish
9 Points
										

Hi,


there r 2of eq. constant


K& K


           rxn       2HI -> H2 +I2


  moles initally   2        0     0


moles @eqlb.   2-2x    x      x   


   


                                Kc   =  x*x/{2-2x}^2 = (0.22)^2/4*(0.78)^2 = 0.19888


 


conc.(C)= P/RT  for gas phase rxn 


                                         RT *(x)= PH2 = PI2   = 0.19888        (same as   Kc bcz  power o RT cancel out  )


                            


                                             


 



7 years ago
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