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If d is the density of a solution of a solute(molar mass = W) in a solvent and "m" is the molality , then prove that molarity(M) of this solution isM = (1000d m)/(1000 + mW)
let weight of the solvent be w gm and weight of the solution be Wgmthen weight of the solvent=(W-w)gm density D=W/V (V=volume of the solution) molality m=(w x1000)/(M'x(W-w)) this implies, (W-w)=(w x1000)/(M'xm) => W=w [(1000+M'm)/M'm] now,molarity M=(w x1000)/(M' x V) => V=(w x1000)/(MxM') nowD=W/V=> D=[{(1000+M'm)/M'm}/{1000/MM'}] => D=[(1000+M'm)xMM'] / [1000x M'm]
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