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Mohini Belani Grade: 12
        

Electrolysis of KBr(aq) gives Br2 at anode but of KF(aq) does not give F2. Give reason for disparity in behaviour.

8 years ago

Answers : (1)

askiitian.expert- chandra sekhar
10 Points
										

Hi Belani,


The activities of the anion based on EOP follows the order:


F- > OH- > Cl- > Br- > I-


At anode least active anion is deactivated.


In aq. solution OH- is present.


So in the electrolysis of KBr(aq), Br- will be deactivated. While in the electrolysis of KF(aq), OH-will be deactivated.


askiitian.expert- chandra sekhar

8 years ago
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