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shiwani sharma Grade:
        


for the first order reaction


A(g) ------: 2B(g) +C(g)


the initial pressure is Pa= 90 mm hg and pressure after 10 min. is 180 mm of hg. find the rate constant.ans is 1.15*10^-3


6 years ago

Answers : (2)

vikas askiitian expert
510 Points
										


A           =>           2B   +   C


p                           0         0                        (initial)                     (at t=0)


P-Po                     2Po       Po                       (final)                       (at t =10)


initial total pressure = P = 90mm


final total pressure = 180mm


 from eq adding all presures we get total pressure = P + 2Po


P +  2Po = 180


90 + 2Po = 180


   Po = 45


for A , initially pressure  = P= 90


        final pressure = P-Po =  90-45 = 45


rate constant (k) = 2.303 log(Pi/Pf) / t


                        = 2.303 log90/45 / t


                        =(2.303)log2/10


                        k = 0.069 min-1


this value of rate constant is in min-1 , 1min = 60sec so


                   K = 0.069/60 sec-1  = 1.15*10-3 sec-1


approve if u like my ans


6 years ago
SAGAR SINGH - IIT DELHI
879 Points
										

Dear student.,


Write the rate of reation in terms of pressure


r=(2.303log P/Po)/time






















































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6 years ago
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