MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Aiswarya Ram Gupta Grade: 12
        

When 1-pentyne (A) is treated with 4N alcoholic KOH at 175°C, it is converted slowly into an equillibrium mixture of 1.3%        1-pentyne (A), 9.5% 2-pentyne (B) and 3.5% of 1.2-pentadiene (C) .The equillibrium was maintained at 175°C. Calculate ΔG° for the following eqilibria.


B ↔ A,      ΔG°1=??


B ↔ C,      ΔG°2=??


From the calculated value of  ΔG°1 &  ΔG°2 indicate the order of stabiity of (A), (B), & (C). Write a reasonable reaction mechanism showing al intermediates leading to (A), (B) & (C).

6 years ago

Answers : (2)

SAGAR SINGH - IIT DELHI
879 Points
										

Dear student,


Gibbs Free Energy (G) - The energy associated with a chemical reaction that can be used to do work.  The free energy of a system is the sum of its enthalpy (H) plus the product of the temperature (Kelvin) and the entropy (S) of the system:



Free energy of reaction (G)



  • The change in the enthalpy (H) of the system minus the product of the temperature (Kelvin) and the change in the entropy (S) of the system:



Standard-state free energy of reaction (G)



  • The free energy of reaction at standard state conditions:



 


Standard-state conditions



  • The partial pressures of any gases involved in the reaction is 0.1 MPa.

  • The concentrations of all aqueous solutions are 1 M.


Measurements are also generally taken at a temperature of 25C (298 K)


 




















































Please feel free to ask your queries here. We are all IITians and here to help you in your IIT JEE preparation.


All the best.


Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.


Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar  respectively : Click here to download the toolbar..


 


Askiitians Expert


Sagar Singh


B.Tech, IIT Delhi



















































6 years ago
Aiswarya Ram Gupta
35 Points
										

thnku

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details
Get extra Rs. 1,272 off
USE CODE: Neerajwin
Get extra Rs. 220 off
USE CODE: Neerajwin

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details