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SOHAN SARANGI Grade:
        

Calculate the pH of a solution obtained by mixing 0.1L of a strong acid solution of pH=4 and 0.2L of a solution of strong base of pH=10

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

ph of strong acid = 4


[H+] = 10-4 = molarity of acid


in 0.1L , moles of acid = 0.1* 10-4


ph of base =10


[H+]=10-10


[OH-]=10-14/10-10=10-4 = molarity of base


in 0.2L , moles of acid = 0.2*10-4


now nutralization will occur and acid is completely nutralised by base , at the end base remaining due to higher concentration....


now final molariry = remaining moles/total vol = (0.2*10-4-0.1*10-4 ) /0.3


                     concentration of base               =10-4/3


[H+] = 3*10-14/10-4 =3*10-10


ph=-loh[H+] = 10-log3= 9.523

6 years ago
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